Question

15/u+2/v=17. 1/u+1/v= 36/5

Answer 1

Explanation:

1/v = x and 1/u = y

15y+2x=17...(1)

y+x=36/5...(2)

Multiply (2) by 2 and subtract (2) from(1)

15y+2x-2(y+x)= 17-72/5 =13/5 =>15y+2x-2y-

2x=13/5 =>13y=13/5 =>y=1/5. Substitute y=1/5 in equation (2) =>x+1/5=36/5=>x=7.

1/v=7 =>v=1/7 and 1/5=1/u =>u=5. u=5 and v=1/7 are the solution for the above pair of equations. Hope it helps you.

Answer 2

$\Large{\textbf{\underline{\underline{According\;to\;the\;Question}}}}$

15/u + 2/v = 17 …………...(1)

1/u + 1/v = 36/5 …………...(2)

Assume

1/u = c & 1/v = n

So,

From (1) we get,

15c + 2n = 17…………..(3)

Also

From (2) we get,

c + n = 36/5 …………..(4)

Now,

From (4) we have

n = 36/5 - c ………..(5)

Putting value of n in (3)

15c + 2n = 17

15c + 2 (36/5 - c) = 17

15c + 72/5 - 2c = 17

13c = 17 - 72/5

13c = (85 - 72)/5

13c = 13/5

c = 13/5 × 1/13

c = 1/5

Substituting value of c in (5)

n = 36/5 - c

n = 36/5 - 1/5

n = (36 - 1)/5

n = 35/5

n = 7

So ,

1/u = c = 1/5

1/v = n = 7

Here

u = 5 & v = 1/6

Therefore,

u = 5 & v = 1/6