Question

15.what sum of money will amount to₹4608,when deposited for 2 years at 20%per annum compounded aunnually?​

Answer 1

$\large{\underline{\underline{\maltese{\green{\pmb{\sf{ \; Given \; :- }}}}}}}$

• Amount = ₹ 4608
• Rate = 20 %
• Time = 2 years

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$\large{\underline{\underline{\maltese{\red{\pmb{\sf{ \; To \; Find \; :- }}}}}}}$

• Principal = ?

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$\large{\underline{\underline{\maltese{\color{darkblue}{\pmb{\sf{ \; Solution \; :- }}}}}}}$

~ Formula Used :

${\color{cyan}{\bigstar}} \; \; {\underline{\boxed{\red{\sf{ A = P \bigg[ 1 + \dfrac{R}{100} \bigg]^n }}}}}$

Where :

• ➢ A = Amount
• ➢ R = Rate
• ➢ P = Principal
• ➢ n = Time

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~ Calculating the Principal :

$\begin{gathered} \implies \qquad{\sf {A = P \bigg[ 1 + \dfrac{R}{100} \bigg]^n }} \\ \end{gathered}$

$\begin{gathered} \implies \qquad{\sf {4608 = P \bigg[ 1 + \dfrac{20}{100} \bigg]^2 }} \\ \end{gathered}$

$\begin{gathered} \implies \qquad{\sf {4608 = P \bigg[ 1 + \cancel\dfrac{20}{100} \bigg]^2 }} \\ \end{gathered}$

$\begin{gathered} \implies \qquad{\sf {4608 = P \bigg[ 1 + 0.20 \bigg]^2 }} \\ \end{gathered}$

$\begin{gathered} \implies \qquad{\sf {4608 = P \bigg[ 1.20 \bigg]^2 }} \\ \end{gathered}$

$\begin{gathered} \implies \qquad{\sf {4608 = P \times 1.20 \times 1.20 }} \\ \end{gathered}$

$\begin{gathered} \implies \qquad{\sf {4608 = P \times 1.44 }} \\ \end{gathered}$

$\begin{gathered} \implies \qquad{\sf {P = \dfrac{4608}{1.44} }} \\ \end{gathered}$

$\begin{gathered} \implies \qquad{\sf {P = \cancel\dfrac{4608}{1.44} }} \\ \end{gathered}$

$\begin{gathered} \implies {\qquad{\pink{\sf { Principal \; = \; ₹ \; 3200 }}}} \\ \end{gathered}$

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~ Therefore :

❛❛ Principle of this sum is ₹ 3200 . ❜❜

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