Question

15. When a body is projected horizontally with velocity u from certain height, it reaches
the ground with velocity 4u. Then height from which it is thrown is​

Answer 1

Answer:

h=3u^2/4

Explanation:

let initial velocity be u

final velocity be 4u.

g=10 m/s^2

By putting the values in v^2-u^2=2gh

16u^2-u^2=20h

15u^2=20h

h=3u^2/4