15. Write the condition for the roots of the equation (a? +b) x2 – 2b (a + c) x +(62 +c?)=0 to be
equal.
Answers
Answered by
1
Answer:
For equal roots discriminant must be equal to zero. So b^2-4ac=0
Step-by-step explanation:
(2b(a+c))^2 -4(a+b)(62+ c) =0 ⇒ 4b^2 (a+c)^2 -4(62a+ac+bc+62c)=0 then one of condition is that if c=0 then (a^2) ×(b^2)=62( a+b) another can be find out by an 4bc(bc-1)+4ac(8b^2-1) +4ab(ab-62((a+b)/ab)=0
Similar questions