Question

15. Write the equation for the reaction taking place at the cathode and anode during electrolysis of
acidulated water. What is the ratio of the volume of the gases obtained at the electrodes?​

Answer 1

Answer:

Hydrogen, Oxygen is the correct answer

Answer 2

Reaction at cathode: H+ + e− → H

H + H → H2

The reaction at anode OH − ion discharge in preference to SO42−

OH− → OH + e−

4OH → 2H2O + O2

Ratio is 2:1

2 volumes of hydrogen:1 volume of oxygen

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