Question

15. Write the Pythagorean triplet whose one number is:
(1) 15
(ii) 26
(iii) 37
[Hint: Take m2 - 1 = 15, m2 + 1 = 26]

Answer 1

Answer:

m-1=15-1=14

m+1=15+1=16

√m=√15=225 like this you can do all

hope it helps please follow and mark as brainliest

Answer 2

now M² + 1 =16+1 =17

2m = 4×2=8

the final pythagorean triplet we got =8,15, 17

check =225+64 = 289