Math, asked by faizalkhan1094, 6 hours ago

15/√x-9/√x=x^1/2, y^10-(36)^5=0 quadratic equations

Answers

Answered by riddhitrivedi842
2

Step-by-step explanation:

We have

9x

2

−15x+6=0

⇒x

2

9

15

x+

9

6

=0 (Dividing throughout by 9)

⇒x

2

3

5

x+

3

2

=0⇒x

2

3

5

x=−

3

2

(Shifting the constant term on RHS)

⇒x

2

−2(

6

5

)x+(

6

5

)

2

=(

6

5

)

2

3

2

(Adding square of half of coefficient of x on both sides)

⇒(x−

6

5

)

2

=

36

25

3

2

⇒(x−

6

5

)

2

=

36

1

⇒x−

6

5

6

1

(Taking square root on both sides)

⇒x=

6

5

+

6

1

=1orx=

6

5

6

1

=

3

2

⇒x=1orx=

3

2

Hence the roots of the equation are 1 and

3

2

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