Math, asked by ThePitttt, 1 month ago

15. X number of men can finish a piece of work in 30
days. If there were 6 men more, the work could be
finished in 10 days less. What is the original number
of men?
(a) 10
(b) 11 (c) 12 (d) 15
(e) 13​

Answers

Answered by Anonymous
2

Required Answer:-

Firstly,

  • Let's understand the relation between the number of men and number of days for doing a piece of work.

  • If there were less number of men, more days will be required to complete the work.

  • They are indirectly proportional to each other. It means, if number of men = x, number of days = m. Then x1.m1 = x2.m2

Now, Let's come to the question.

X men take 30 days to complete a work.

1 men will takes 30 × X days to complete then. (From the above relation).

And,

If there were 6 more men, then number of men now is X + 6. No. of days is 30 - 10 = 20 days.

X + 6 men take 20 days to complete.

1 men will take (X + 6)20 days then..

That means,

⇒ 30X = (X + 6)20

⇒ 30X = 20X + 120

⇒ 10X = 120

⇒ X = 12 men

Initially,

The no. of men were X i.e. 12 (Option C)

Answered by Anonymous
0

Answer:

X number of men can finish a piece of work in 30 days. ==> Total work = 30X Men days. -- (1)

X number of men can finish a piece of work in 30 days. ==> Total work = 30X Men days. -- (1)If there were 6 men more, the work could be finished in 10 days less. ==> Total work = (X+6)*20 days -- (2)

X number of men can finish a piece of work in 30 days. ==> Total work = 30X Men days. -- (1)If there were 6 men more, the work could be finished in 10 days less. ==> Total work = (X+6)*20 days -- (2)By (1) and (2) we have:

X number of men can finish a piece of work in 30 days. ==> Total work = 30X Men days. -- (1)If there were 6 men more, the work could be finished in 10 days less. ==> Total work = (X+6)*20 days -- (2)By (1) and (2) we have:30X = (X+6)*20 => 10X = 120 => X = 12 men.

Step-by-step explanation:

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