Math, asked by laibaijaz693, 2 months ago

15 x² + 2ax - a² = 0 by completing square

Answers

Answered by itsnasreensahaikh
0

Step-by-step explanation:

15 x² + 2ax - a² = 0 15 x² + 2ax - a² = 0 15 x² + 2ax - a² = 0 15 x² + 2ax - a² = 0 15 x² + 2ax - a² = 0

Answered by mirgalriddhi
0

Step-by-step explanation:

Simplifying

15x2 + 2ax + -1a2 = 0

Reorder the terms:

2ax + -1a2 + 15x2 = 0

Solving

2ax + -1a2 + 15x2 = 0

Solving for variable 'a'.

Factor a trinomial.

(-1a + -3x)(a + -5x) = 0

Subproblem 1

Set the factor '(-1a + -3x)' equal to zero and attempt to solve:

Simplifying

-1a + -3x = 0

Solving

-1a + -3x = 0

Move all terms containing a to the left, all other terms to the right.

Add '3x' to each side of the equation.

-1a + -3x + 3x = 0 + 3x

Combine like terms: -3x + 3x = 0

-1a + 0 = 0 + 3x

-1a = 0 + 3x

Remove the zero:

-1a = 3x

Divide each side by '-1'.

a = -3x

Simplifying

a = -3x

Subproblem 2

Set the factor '(a + -5x)' equal to zero and attempt to solve:

Simplifying

a + -5x = 0

Solving

a + -5x = 0

Move all terms containing a to the left, all other terms to the right.

Add '5x' to each side of the equation.

a + -5x + 5x = 0 + 5x

Combine like terms: -5x + 5x = 0

a + 0 = 0 + 5x

a = 0 + 5x

Remove the zero:

a = 5x

Simplifying

a = 5x

Solution

a = {-3x, 5x}

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