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15/y+60/x=1 and 4/y+8/x=1/6 find the value of x & y​

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Write the number of solutions of the following pair of linear equations:

x+2y−8=0,2x+4y=16

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Answer

x+2y=8

And 2x+4y=16

These given equations are in the form:

a

1

x+b

1

y+c

1

=0 and

a

2

x+b

2

y+c

2

=0

Where

a

1

=1,b

1

=2 and c

1

=8

a

2

=2,b

2

=4 and c

2

=16

a

2

a

1

=

2

1

,

b

2

b

1

=

4

2

=

2

1

As we know, the condition for the equations to have infinitely many solutions is

a

2

a

1

=

b

2

b

1

=

c

2

c

1

So, system has infinitely many solutions.