Question

15 year ago, A man was 5 time old has the son . if at present, he is twice as old has his son , find their present age.​

Answer 1

Answer:

At present

Son age = 20years

Father 's age = 40years

Step-by-step explanation:

Let son age = x

so, Father's age = 2x

At 15 years ago

Son age = (x - 15)

Then, Father 's age = 2x-15

Therefore, according to question

Father's age = 5*(son age)

2x-15 = 5*(x - 15)

2x-15 = 5x -75

-5x+2x = -75+15

-3x = -60

x= 20

Therefore, son age = 20years

Father's age = 40years

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