Question

15 years ago a man was 5 times older as his son. if at present he is twice as old as his son find their present age. ​

Answer 1

Answer:

the present age of a man =30 years

and the present age of his son =6 years

Step-by-step explanation:

Let, the present age of a man =x years

and the present age of his son =y years

According to the question,

x=5y  and x+2=4(y+2)

∵x+2=4(y+2)

⟹5y+2=4y+8

⟹5y−4y=8−2

∴y=6

Hence, x=5y=5(6)=30

i.e., the present age of a man =30 years

and the present age of his son =6 years

Answer 2

Answer:

Suppose the age of father and son be x and y respectively.

x=2y...equation(i)

15 years ago,

x-15=5(y-15)

or, x-15=5y-75

From equation(i)

or, 2y-15=5y-75

or, 2y-5y=15-75

or, -3y=-60

or, y=-60/-30

•°•y=2yrs

From equation (i)

x=2*2

•°•x=4 years