Math, asked by vigyatatoppo00, 3 months ago


15 years ago, Narendra Father's age was four times of Narendra's age. Now Narendra
father's age is 6 years more than twice of Narendra's age. Find their ages?

Answers

Answered by BrainlyYuVa
1

Solution

Given :-

  • 15 years ago, Narendra Father's age was four times of Narendra's age

  • Now Narendrafather's age is 6 years more than twice of Narendra's age.

Find :-

  • Present age of Narendra & Narendra Father 's

Explanation

According to question

Case 1.

==> present age of Narendra Father's = (x + 6)

==> present age of Narendra = x

Case 2.

==> (x + 6 - 15) = 4(x - 15)

==> x - 9 = 4x - 60

==>4x - x = -9 + 60

==> 3x = 51

==> x = 51/3

==> x = 17

Hence

  • Present age of Narendra Father's = (x + 6) = 17 + 6 = 23 years
  • Present age of Narendra = 17

____________________

Answered by gnaman183
0

Answer:

Let the current age of Narendra be = x

so current age of narendra's father = 2x + 6

also 15 years ago narendra age was  = x - 15

and his father age was = 4(x-15)  

Step-by-step explanation:

According to the given equations his father's present age can be

written as

=> (2x + 6) - 15 = 4(x - 15)

=>  2x + 6 - 15 = 4x - 60

=>  +6 -15 + 60 = 4x - 2x

=>  51 = 2x

x = 25.5

Therefore, present age of narendra is = 25.5 years

and Narendra's Father is  = (2* 25.5 + 6) = 57 years

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