Question

15 years ago the average age of a family of four members was 40 years. Two children were bom in that span of 15 years. The present average age of the family remained unchanged. Among the two children who were bom in between the 15 years. If the older child at present is 8 years more than the younger one, what is the respective ratio between the present age of the older child and the present age of the younger child 7

(a) 9 : 4
(b) 7 : 3 => ........... (ANS)
(c) 7 : 6
(d) 7 : 4
(e) 9 : 5

Answer 1

i hope this helps you

Answer 2

$\huge \red{heya \: dear \: mod}$

$\bold \red{answer = = > }$

$the \: total \: age \: of \: 4 \: members$

$\bold \red{ = = > 160years}$

$the \: total \: age \: of \: 6 \: members \:$

$at \: present \bold \red{ = = > 240years}$

$\bold \red{difference \: of \: ages }$

$\bold \red{(240 - 160) = 80years}$

$after \: 15 \: years \: the \: 4 \: member$

$\bold \red{is \: 60years}$

$so$

$the \: age \: of \: \bold{new \: born \: baby}$

$\bold\red{is \: (80 - 60) = 20years}$

$hence$

$(x + 8) + x - 20 = 0$

$2x + 8 = 20$

$2x = 20 - 8 = 12$

$x = 12 \div 2 = 6$

$\bold\red{x = 6}$

:$so$

$(x + 8) = 14 \: and \: x \: = 6$

$\bold \red{ratio = 14 : 6 = 7 :3}$

$\bold{hence}$

$\bold \red{ratio \: = \: 7 :3}$

$<font color = gold><marquee>be brainly!!☺☺$