Question

(15
.
you
15. Find a relation between x and y such that the point (x, y) is equidistant from the poin
(-2,8) and (-3,-5)​

Answer 1

Answer:

hope it is useful thanks

Answer 2

Answer:

As the point is equidistant from the points (-2,8) and (-3,-5)

$x = \frac{x_1 \: + x_2}{2} \\ \\ x = \frac{ - 2 + ( - 3)}{2} \\ \\ x = \frac{ - 2 - 3}{2} \\ \\ \boxed{x = \frac{ - 5}{2} }$

$y = \frac{y_1 + y_2}{2} \\ \\ y = \frac{8 + ( - 5)}{2} \\ \\ y = \frac{8 - 5}{2} \\ \\ \boxed{ y = \frac{3}{2} }$

The points (x,y) is (½ , 3/2)