Question

150 coins are placed in three different bags in the ratio 2:5:3. Find the number of coins in the bag which contains the most number of coins.



75 coins

73 coins

78 coins

72 coins


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Answer 1

Ratio of coins in three bags =2:5:3

Which means :-

(i) Number of coins in the first bag :-

$= \frac{2}{10} \times 150$

$= \frac{300}{10}$

$= \bold{30}$

Thus, number of coins in the first bag =30

(ii) Number of bags in the second bag :-

$= \frac{5}{10} \times 150$

$= \frac{750}{10}$

$= \bold{75}$

Thus, number of coins in the second bag =75

(iii) Number of coins in the third bag :-

$= \frac{3}{10} \times 150$

$= \frac{450}{10}$

$= \bold{45}$

Thus, number of coins in the second bag =45

As the number of coins in all the bags is adding up to form 150 coins, we can conclude that we have found out the correct number of coins in each bag.

Thus, number of coins in the bag with the highest number of coins =75 coins

Therefore, the correct option is :-

$\bold{(a) \: 75 \: coins}$