Question

150. In the given circuit voltmeter shows a reading of
4 V, then the power developed across R resistance
will be
2k 2
10 V-T
RV
(1) 15 mW
(3) 12 mW
(2) 14 mW
(4) 10 mW​

Answer 1

Answer:

12mW please vote as the brainliest answer

Answer 2

Explanation:

By assuming zero volt at one end of the battery=

across 2KΩ resistance = ΔV=IR

(10−4)=I×(2000)

6=I×(2000)

I= 6/2000

=3mA

Now power generated through resistance R= (voltage across resistance R)×(current flowing through resistance R)

P = 4×3 m W

P = 12 m W

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