150 Joule of heat is produced each second in a 6Ω resistance. Find the potential 2
difference across the resistor
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Answer:
The produced heat is given as,
H=I^2 Rt
150=I^2×6×1
I=3.53A
The potential difference is given as,
V=IR
=3.53×6
=21.18
Thus, the potential difference across the resistor is 21.18 V.
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