Question

150 ml, 2 M sulphuric acid solution is mixed with
350 ml water. The final molarity of the solution is
(1) 1.5 M
(2) 0.6 M.
(3) 2.1 M
(4) 1.7 M​

Answer 1

Answer:M1V1=M2V2 ie 2*150=M2(500) so M2 =0.6. We write vol of final sol in V2.

Explanation:

Answer 2

Answer:

As,

M1V1=M2V2

2×150=M2×500(volume of total solution)

M2=500/300

M2=5/3

M2=1.67

=1.7M(approx)