Question

150 ml of a gas at ntp were taken to 20 Celsius and 0.96 bar pressure .what is the change in volume of the gas
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Answer 1

When 150 ml of a gas at NTP were taken to 20 Celsius and 0.96 bar pressure, then change in volume of the gas is 8 ml.

Step-by-step Explanation:

This question uses the concept of Universal Gas equation.

Given:

• Initial conditions is NTP

• $P_1= 1 atm= 1.013 \hspace{1 mm}bar$  (initial pressure)
• $T_1= 20\textdegree C= 293 K$ (initial temperature)
• $V_1=150 ml=0.15 \hspace{1 mm}litres$ (initial volume)
• $P_2=0.96\hspace{1 mm}bar$ (final pressure)
• $T_2=20\textdegree C= 293 K$  (final temperature)

To be found:

the value of $(V_2-V_1)$, the change in volume of the gas

Formula to be used:

• The Universal Gas equation gives the relation between the Pressure, Volume and temperature of a gas.
• $\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

We can substitute the given values of initial and final conditions into the Gas equation,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

⇒$\frac{1.013*0.150}{293} = \frac{0.96*V_2}{293}$

We can now simplify the above equation to find out the value of $V_2$

⇒$V_2=\frac{1.013*0.150*293}{293*0.96} = 0.158 \hspace{1 mm} litres = 158 ml$

Therefore, $V_1= 150 ml$ and $V_2=158 ml$

So, we can get the change in volume of the gas,  $V_2-V_1=(158-150)ml= 8 ml$

So, when 150 ml of a gas at NTP were taken to 20 Celsius and 0.96 bar pressure, then change in volume of the gas is 8 ml.