Math, asked by rupaliparida2972, 10 months ago

150 spherical marbles,each of diameter 1.4cm, are dropped in a cylindrical vessel of

diameter 7cm containing some water and are completely immersed in water.Find the

rise in the level of water in the vessel.

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Answers

Answered by AwesomeSoul47
8

Answer:

hey friend here is your answer ..,,,,,,,

Diameter of marble = 1.4 cm

Radius of marble = 0.7 cm

Number of marbles = 150

Diameter of cylinder = 7cm

Radius of cylinder = 3.5cm

Let the height of the water raised when 150 spheres are dropped in the vessel.

Volume of 150 marbles = Volume of water raised by height 'h' inside the vessel

150 x 4 over 3 x straight pi x 0.7 x 0.7 x 0.7 = straight pi x 3.5 x 3.5 x h [vol. of sphere = 4 over 3 straight pi r3 and vol. of cylinder = straight pi r2 h]

50 x 4 x (0. 7)3 = (3.5)2 x h

200 x 0.343 = 12.25 x h

68.6 / 12.25 = h

5.6 = h

Height of water raised (h) = 5.6 cm

Step-by-step explanation:

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Answered by MrEccentric
0

Hey mate!

Thank you for asking this question! ❤

Answer:

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The rise in level of water in the vessel is 5.6 cm.

Step-by-step explanation:

Let 'h’ be the rise in level of water in the cylindrical vessel.

Given :

Diameter of the cylindrical vessel = 7 cm

Radius of the cylindrical vessel , R = 7/2 = 3.5 cm

Diameter of the spherical marble = 1.4 cm

Radius of the spherical marble , r = 1.4/2 = 0.7 cm

Volume of each marble = 4/ 3 × π r³

Volume of 150 marble = 150 × 4/ 3 × π (0.7)³ ………(1)

Volume of water displaced in the cylindrical vessel = πR²h = π(3.5)²× h ……….(2)

Since, volume of water displaced in the cylindrical vessel is equal to the volume of 150 spherical marbles

Volume of water displaced in the cylindrical vessel = Volume of 150 spherical marbles

π(3.5)²× h = 150 × 4/ 3 × π (0.7)³

(3.5)² × h = 150 × 4/ 3 × (0.7)³

h = [150 × 4 × (0.7)³] /[ (3.5)² × 3]

h = [150 × 4 × 0.7 × 0.7 × 0.7] /[ 3.5 × 3.5 × 3]

h = (50 × 4 × 0.7) / ( 5 × 5)

h = (200× 0.7)/ 25 = 8 × 0.7 = 5.6

h = 5.6 cm

Hence, the rise in level of water in the vessel is 5.6 cm...

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