150 spherical marbles,each of diameter 1.4cm, are dropped in a cylindrical vessel of
diameter 7cm containing some water and are completely immersed in water.Find the
rise in the level of water in the vessel.
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Answers
Answer:
hey friend here is your answer ..,,,,,,,
Diameter of marble = 1.4 cm
Radius of marble = 0.7 cm
Number of marbles = 150
Diameter of cylinder = 7cm
Radius of cylinder = 3.5cm
Let the height of the water raised when 150 spheres are dropped in the vessel.
Volume of 150 marbles = Volume of water raised by height 'h' inside the vessel
150 x 4 over 3 x straight pi x 0.7 x 0.7 x 0.7 = straight pi x 3.5 x 3.5 x h [vol. of sphere = 4 over 3 straight pi r3 and vol. of cylinder = straight pi r2 h]
50 x 4 x (0. 7)3 = (3.5)2 x h
200 x 0.343 = 12.25 x h
68.6 / 12.25 = h
5.6 = h
Height of water raised (h) = 5.6 cm
Step-by-step explanation:
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Answer:
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The rise in level of water in the vessel is 5.6 cm.
Step-by-step explanation:
Let 'h’ be the rise in level of water in the cylindrical vessel.
Given :
Diameter of the cylindrical vessel = 7 cm
Radius of the cylindrical vessel , R = 7/2 = 3.5 cm
Diameter of the spherical marble = 1.4 cm
Radius of the spherical marble , r = 1.4/2 = 0.7 cm
Volume of each marble = 4/ 3 × π r³
Volume of 150 marble = 150 × 4/ 3 × π (0.7)³ ………(1)
Volume of water displaced in the cylindrical vessel = πR²h = π(3.5)²× h ……….(2)
Since, volume of water displaced in the cylindrical vessel is equal to the volume of 150 spherical marbles
Volume of water displaced in the cylindrical vessel = Volume of 150 spherical marbles
π(3.5)²× h = 150 × 4/ 3 × π (0.7)³
(3.5)² × h = 150 × 4/ 3 × (0.7)³
h = [150 × 4 × (0.7)³] /[ (3.5)² × 3]
h = [150 × 4 × 0.7 × 0.7 × 0.7] /[ 3.5 × 3.5 × 3]
h = (50 × 4 × 0.7) / ( 5 × 5)
h = (200× 0.7)/ 25 = 8 × 0.7 = 5.6
h = 5.6 cm
Hence, the rise in level of water in the vessel is 5.6 cm...
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