1500 Calories of heat is supplied to 150 grams of water find the rise in temperature specific heat of water is 1cal
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Q = mSΔT
ΔT = Q / (mS)
= 1500 cal / (150 g × 1 cal / (g °C))
= 10 °C
∴ Temperature is raised by 10 degrees Celsius
[Note: We can also say that temperature is raised by 10 Kelvin]
ΔT = Q / (mS)
= 1500 cal / (150 g × 1 cal / (g °C))
= 10 °C
∴ Temperature is raised by 10 degrees Celsius
[Note: We can also say that temperature is raised by 10 Kelvin]
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