1500 families with 2 children were selected randomly and the following data were recorded.
Number of girls in a family, 2,1,0.
Number of families.
475,814,211.
Compute the probability of a chosen at random having.
1) 2 girls 2) 1 girls 3) no girl.
Answers
Answered by
1
Formula of probability= No. of favourable cases/ No. of total cases
1) P(2girls)= 475/1500= 0.32
2) P(1 girl)=814/1500=0.54
3)P(no girl)= 211/1500=0.14
Answered by
8
Answer:
hey mate your answer
Step-by-step explanation:
(i) Number of families having 2 girls =475
Total families =475+814+211=1500
P(2 girls) =Total families475
=1500475=6019
(ii) P(1 girl)=1500814=750407
(iii) P(No girl) =1500211
Sum of all these probabilities
=6019+750407+1500211
=1500475+814+211
=15001500=1
Sum of these probabilities =1
hope it helps you
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