Physics, asked by nitishbharadwajd, 5 months ago

1500 families with 2 children were selected randomly, and the following data were
recorded​

Answers

Answered by XxArmyGirlxX
3

Answer:

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(i) Number of families with 2 girls = 475

Total number of families = 150

P(E) =(Number of favourable outcomes)/(Total number of event)

=475/1500

=19/60

(ii) Number of families with 1 girl = 814

P(E) = (Number of favourable outcomes)/(Total number of event)

=814/1500

=407/750

(iii) Number of families with no girl = 211

P(E) = (Number of favourable outcomes)/(Total number of event)

=211/1500

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