Question

1500 ml flask 400 gram of oxygen 800 degree Celsius calculate pressure

Answer 1

Answer:

ANSWER

(a) No. of moles of O

2

=

1000×32

400

=0.0125

No. of moles of H

2

=

1000×2

60

=0.03

Partial pressure of O

2

=

1.5

0.0125×0.0821×373

=0.255 atm

Partial pressure of H

2

=

1.5

0.03×0.0821×373

=0.612 atm

Total pressure =0.255+0.612=0.867 atm

(b) 2H

2

+O

2

⟶2H

2

O

Initial 0.03 0.0125 0

After reaction 0.005 0 0.025

Partial pressure of H

2

=

1.5

0.005×0.0821×373

=0.102 atm

Partial pressure of H

2

O=

1.5

0.025×0.0821×373

=0.51 atm