Math, asked by anmolali3765, 3 months ago

1500 rupees is invested in a scheme A at R% p.a. simple interest. Another amount of 1500-x is invested in scheme B at 2R% p.a.simple interest. After 4 years, interest earned from scheme A is 25% less than that of scheme B. find x.

Answers

Answered by prasanthikuchipudi
10

Answer:

x=500

Step-by-step explanation:

Given,

1500 rupees is invested in a scheme A at R% p.a. simple interest for 4 years

SI=1500*R*4/100

  =60R

Another amount of 1500-x is invested in scheme B at 2R% p.a.simple interest.

SI=((1500-x)*2R*4)/100

  =(2R(1500-x))/25

A is 25% less than that of scheme B

A will be 75% and B will be 100%

by dividing A by B

60R/(2R(1500-x))/25=75/100

by solving we get x=500

Brainliest my solution

Answered by Shivaya007
0

A ko 1/4 km mila h interest B se... 3:4

Agr B ka A k comparison m twice of rate of interest na hota to interest B ko 4 na milta blki 2 milta...

A:B=3:2

Ab rate or time constant h dono ka.... To jo ye ratio aya vo directly proportional h principal k... 3 ke value 1500 h to 2 ke value 1000....mtlb x ke value 500₹ h!

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