Question

150g CaCO3 calculate the number of moles atoms and molecules​

Answer 1

Answer:

It would Jave 1.5 moles

Explanation:

Molecular Mass Of CaCO3

$CaCO3 \\ = )40 + 12 +( 3 \times 16) \\ = )40 + 12 + 48 \\ = )100u$

Gram Molecular Mass = 100g

NOW:-

Number Of Moles In 100 g = 1

Number Of Moles In 1 g = 1/100

Number Of Moles In 150 g :-

$\frac{1}{100} \times 150 \\ = )1.5$

Hope it helped

Answer 2

Answer:

hope so it will help you..

Explanation:

ANSWER

M.wt of CaCO

3

=100

number of moles of CaCO_3 present in 50gm =

100

50

=0.5

1 mole of CaCO

3

= 3 moles of O

2

0.5 moles of CaCO

3

has 1.5 moles of oxygen.

1mole=6.022∗10

23

particles

∴ 50g of CaCO

3

=1.5∗(6.022∗10

23

)=9.035∗10

23

oxygen atoms.