Question

150gm of zinc is heated to high temperature and placed in 0.5 litres of water at 30° if the resultant temperature of mixture is found to be 35° the intial temperature of zinc (specific heat of zinc is 0.093)​

Answer 1

Answer:

610. g) (95.3 °C − x) (0.387 J g¯1 K¯1) = (45.0 g) (x − 36.5 °C) (4.184 J g¯1 °C¯1) + [(10.0 J/K) (x − 36.5 °C)]

Comment: The K and the °C cancel because the °C in this problem is a temperature difference (not one single specific value) and the "size" of one K = one °C.