Question

(151) An object is projected with initial velocity of 100 ms' and angle of 60. Find the verticle velocity
when its horizontal displacement is 500 m. (g = 10 ms")
(A) 93.35 ms (B) –93.35 ms () -8.65 ms." (D) 98 ms
(152) Angle of projection of a priti
,​

Answer 1

Answer:

Explanation:

See this is a question from projectile motion.

Given initial velocity = 100 m/s

Angle of Projection = 60

Now its horizontal displacement is given = 500m

Say at a time (t) this situation is occuring.

Therefore

Sₓ=uₓt

500= 100cos60*t

t= 10

Now Vy= Uy + Ayt

Vy= 50√3 - 10*10 = 50*1.73-100 = -13.5