Question

151.
Tonic Equilibrium
If 50 ml of 0.2 M KOH is added to 40 ml of 0.5 M HCOOH, the pH of the resulting solution is (K = 1.8 x
10+)
(A)3.4
(B) 7.5
(C) 5.6
(D) 3.75​

Answer 1

The pH of the resulting solution is 3.4

Explanation:

First consider the equation based on the given data

KOH+HCOOH----->HCOOK+H2O

Formula for pH calculation is given below

$pH=-logK_{a} +log\frac{[salt]}{[Acid]}$

so

$[salt]=\frac{0.2*50}{1000} =0.01$

$[Acid]=\frac{0.5*40}{1000} =0.02$

$pH=-log(1.8*10^{-4} )+log\frac{0.01}{0.02}$

$pH=4-log(1.8)+log0.5$

$pH=4-log(1.8)-0.301$

$pH=3.4$

Finally the value of pH of the resulting solution is 3.4

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