Question

152 ml of a gas at S.T.P. was taken to 20°C and 729 mm pressure.
What was the change in the volume of the gas.​

Answer 1

Answer:

Explanation:

$Given$

$v_{1} = 152 ml$

$p_{1} = 1 atm = 760 mm$

$t_{1} =273.15 k$

$v_{2} = ?$

$p_{2} = 729 mm$

$t_{2} = 20^{o} C \\or \\293.15 K$

$V_{2} = \frac{P_{1} V_{1} }{T_{1} } * \frac{T_{2} }{P_{2} }$

$= \frac{760*156*293.15}{273.15*729} = 170 ml$

change in volume $= v_{2} - v_{1} = 170 - 152 = 18 ml$

Answer 2

Explanation:

hyy here is your answer