Question

152 ml of a gas at S.T.P. was taken to 20oC and 729 mm pressure.

What was the change in the volume of the gas.
Please answer fast and correct its very urgent.. please​

Answer 1

Answer:

Given

V1=152mLV1=152mL

P1=1atm=760mmP1=1atm=760mm

T1=273.15KT1=273.15K

V2=?V2=?

P2=729mP2=729m

T2=20∘CT2=20∘C or 293.15K293.15K

∴V2=P1V1T1×T2P2=760×152×293.15273.15×729=170mL∴V2=P1V1T1×T2P2=760×152×293.15273.15×729=170mL

∴Chan≥∈volume=V2−V1=170−152=18mL