Math, asked by Muksor, 5 months ago

154(i) sec^6 e = 3tan^2sec^2 e + 3tan?​

Answers

Answered by monkeygamer163
0

Answer:

LHS

Step-by-step explanation:

RHS = sec^6 a = (sec^2 a)^3

                         = (1+tan^2a)^3

                         = 1 + (tan^2 a)^3 + 3 tan^2 a (1+tan^2 a)

                         = 1 + tan^6 a + 3 tan^2 a * sec^2 a.

                         = LHS.

give a good ratings

Similar questions