Question

156 gram of Al(OH)3present in 8 litre of solution​

Answer 1

Hi Friend

Here You need to calculate the Molarity

First calculate the number of moles of Al(OH)3 so the moles would be

156/78=2 mol

now using the molarity formula moles /volume (Litre)

2/8=1/4=0.25

Hope answers the question

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