Chemistry, asked by Tulsirani100, 11 months ago

158. During measurement of electrode potential of half - cell
coupled with S.H.E, bubbles were formed in the
interior of solution of S.H.E. It shows that S.H.E act as:
(a) Anode
(b) Cathode
(c) Anyone
(d) Can't be predicted​

Answers

Answered by PSN03
4

Answer:

b.Cathode

Explanation:

Prerequisite knowledge:

SHE :

It consists of platinum wire sealed in a glass tube and has a platinum foil attached to it.The foil is coated with finely divided platinum and acts as platinum electrode.It is dipped into acid solution containing H⁺ ions in 1M concentration.

Pure hydrogen gas at 1 atm is constantly bubbled into the solution at constant temperature of 25° C or 298 K.

The following reactions occur depending on whether it acts as a cathode or anode.

    1.  At anode:

        H₂ (g)-----------> 2 H⁺ + 2 e⁻        (equation 1)

    2. At cathode

        2 H⁺ + 2 e⁻-----------> H² (g)        (equation 2)

Approach to the question:

  • According to our question we find that some bubbles are formed at SHE.
  • This is only possible if some gaseous products are obtained.
  • From the above two equations, only equation 2 gives a gaseous product ie H₂.
  • Hence we can say that according to the equation the SHE should act as cathode.

Therefore we can say that SHE acts as Cathode.

Hope this helps.

Answered by renuhkkohli693
0

Answer:

option B is the correct answer

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