Question

15cc of gaseous hydrocarbon required 45cc of oxygen for complete combustion. if 30cc of CO2 is formed, the formula of the gaseous compound is​

Answer 1

Answer : The formula of gaseous hydrocarbon will be $C_2H_4$

Explanation :

The reaction can be shown as:  

$C_xH_y+(x+\frac{y}{4})O_2\rightarrow xCO_2+\frac{y}{2}H_2O$

The ratio of the volumes of oxygen and hydrocarbon used in the combustion = 45 : 15 = 3 : 1

The ratio of carbon dioxide produced and hydrocarbon used = 30 : 15 = 2 : 1

That means,

$x+\frac{y}{4}=3$    and    x = 2

Now put the value of 'x' in this expression we get:

$x+\frac{y}{4}=3$

$2+\frac{y}{4}=3\\\\\frac{y}{4}=1\\\\y=4$

Thus, the formula of gaseous hydrocarbon will be $C_xH_y=C_2H_4$

Answer 2

Explanation:

pls check the above photo's