Question

15g of KMnO, in acidic medium equal to (Atomic mass of Mn = 55)
(A) 0.095 moles
(B) 0.477 gram equivalents
(C) 9.54 L of 0.05N KMnO,
(D) 10 ml of 0.5M KMnO,​

Answer 1

31.4g

As Mn7+ in KMnO4 changes to Mn2+ in acidic medium; it's equivalent weight becomes M/5. (where M is Molar mass of KMnO4.) Since mass of KMnO4 is 158, Equivalent Weight in acidic Medium is 31.4g.