Question

15g of N2 and 3g of H2 are mixed to produce ammonia . Identify the limiting reagent and calculate the amount of ammonia formed ? ​

Answer 1

Answer:

The limiting reagent is hydrogen

Amount of ammonia formed is 34g

Explanation:

N₂ + 3H₂ gives 2NH₃ is the stochastic equation. Thus 1 mole of N2 reacts with 3 moles of Hydrogen to give 2 moles of ammonia.

Molecular mass of nitrogen = 14g

Amount of nitrogen present = 15g

Amount of hydrogen present = 3g

The molecular mass of hydrogen = 1g

No of moles = mass of substance/molecular mass of a substance

No of moles of Nitrogen = 15/14 = 1.07 moles

No of moles of hydrogen = 3/1 = 3 moles

Thus when 3 moles of hydrogen reacts with 1 mole of nitrogen, 0.07 moles of nitrogen is remaining. Thus limiting reagent is hydrogen.

2 moles of ammonia is formed are formed in this reaction.

molecular mass of ammonia = 17g, hence 34g of ammonia is formed