15g of oxalic acid present in 150g of aqueous solution find mass %
Answers
Answered by
6
Explanation:
mass% = mass of solute/ mass of solution × 100
so we know that which mole is in less amount that is solute. so here oxalic acid is solute
15/15+150 = 15/165 = .090× 100 = 9.0%
Answered by
4
Answer:
10%
Explanation:
mass=w/w+W*100
w=15g
w+W=150g
15/150*100
=10%
Similar questions