15lm (2p²–2q²) ÷ 3l (p + q), Factorize the expression and divide them as directed.
Answers
Answered by
4
= 3 × 13 × 2 × y × y × y × [(5y)2 − (7)2]
= 3 × 13 × 2 × y × y × y (5y − 7) (5y + 7)
26y2(5y + 7) = 2 × 13 × y × y × (5y + 7)
39y3(50y2 − 98) ÷26y2 (5y + 7)
= 3 × 13 × 2 × y × y × y (5y − 7) (5y + 7)
26y2(5y + 7) = 2 × 13 × y × y × (5y + 7)
39y3(50y2 − 98) ÷26y2 (5y + 7)
Answered by
2
Answer:
10m(p-q)
Step-by-step explanation:
We have to find the value of 15lm(2p²-2q²) ÷ 3l(p+q).
So, to evaluate the above operation we will first factorize the first term.
Hence, we have, 15lm(2p²-2q²)
=30lm(p²-q²) {Taking 2 as a common and multiplying with 15}
=30lm (p+q)(p-q) {Using the formula (a²-b²)= (a+b)(a-b)} .... (1)
Now, we will divide expression (1) with 3l(p+q), and we will get the result as [30lm (p+q)(p-q)/3l(p+q)] = 10m(p-q) (Answer)
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