Question

15m ladder reached a window 12m high from the ground distance of the foot of ladder from the wall

Answer 1

Correct question:-

A 15m long ladder reached a window 12m high from the ground on placing it against a wall at a distance a. Find the distance of the foot of the ladder from the wall

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In given figure :-

• A 15m long ladder reached a window 12m high from the ground on placing it against a wall at a distance a.

To find:-

• The distance of the foot of the ladder from the wall.

$\huge\sf{Solution:}$

AC = 15 metres long ladder

AB = 12 metres high

CB = 'a' metres

Now,

∆ ABC is a right angled triangle.

Angle ABC = 90°.

By pythagoras Theorem :-

(AC)^2 = (BC)^2 + (AB)^2

(15)^2 = (a)^2 + (12)^2

225 = (a)^2 + 144

225 - 144 = (a)^2

81 = (a)^2

9 = a

Therefore  , 

The distance of the foot of the lader from the wall is 9 m.

Answer 2

Solution:

AC = 15 metres long ladder

AB = 12 metres high

CB = 'a' metres

Now,

∆ ABC is a right angled triangle.

Angle ABC = 90°.

By pythagoras Theorem :-

$(AC)^2 = (BC)^2 + (AB)^2 \\ </p><p></p><p>(15)^2 = (a)^2 + (12)^2 \\ </p><p></p><p>225 = (a)^2 + 144 \\ </p><p></p><p>225 - 144 = (a)^2 \\ </p><p></p><p>81 = (a)^2 \\ </p><p></p><p>9 = a \\ </p><p>$

Therefore ,

The distance of the foot of the lader from the wall is 9 m

$hope \: its \: help \: u$