Question

15th term of A.P. 1/3 ,5/3,9/3,13/3​

Answer 1

given ap is 1/3,5/3,9/3......

a = 1/3

d = a2-a1

= 5/3 - 1/3

= 4/3

nth term of an ap is

an = a + (n-1) d

a15= 1/3 + 14-1 × 4/3

= 1/3 + 52/3

= 53/3

15th term of the ap is 53/3

MARK IT AS BRAINLIEST PLS

Answer 2

Hey friend, Here is your answer-

a=t1= 1/3 and n = 15

d= 5/3 - 1/3

= 5-1/3

= 4/3

by using formula,

tn = a + (n-1)d

$t15 = \frac{1}{3} + (15 - 1) \times \frac{4}{3} \\ \: \: \: \: \: \: \: \: = \frac{1}{3} + \frac{56}{3} \\ \: \: \: \: \: \: \: \: \: = \frac{57}{3} \\ t15 = 19$

Hope it will help you.

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