Question

15th term of an A.P x-7, x-2 , x+3 ........... is

Answer 1

Answer:

x + 63

Step-by-step explanation:

First term of AP = x-7

Difference of AP = (x-2) - (x-7)

= x - 2 - x + 7

= 5

15th term of AP = (x-7) + [(15-1) X 5]

= (x-7) + (14 X 5)

= x - 7 + 70

= x + 63

Answer 2

Given that : a = x-7, n = 15 and

d = x-2 -(x-7) = 5

Now, 15th term = a + (n-1)d

=> 15th term = x-7+(15-1)5

=> 15th term = x-7+14×5

=> 15th term = x-7+70 = x+63