15th term of AP 1/3,5/3,9/3,13/3. is :-
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Step-by-step explanation:
We have t
1
=7,t
2
=13,t
3
=19,t
4
=25...
The common difference d=t
2
−t
1
=13−7=6
First term a=7,t
15
=?
We know that
t
n
=a+(n−1)d
t
15
=7+(15−1)×6
∴ t
15
=7+14×6
∴ t
15
=7+84
∴t
15
=91
∴ t
15
=91
∴ The fifteenth term of the A.P is 91.
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