Question

15th term of AP 1/3,5/3,9/3,13/3. is :-​

Answer 1

Step-by-step explanation:

We have t

1

=7,t

2

=13,t

3

=19,t

4

=25...

The common difference d=t

2

−t

1

=13−7=6

First term a=7,t

15

=?

We know that

t

n

=a+(n−1)d

t

15

=7+(15−1)×6

∴ t

15

=7+14×6

∴ t

15

=7+84

∴t

15

=91

∴ t

15

=91

∴ The fifteenth term of the A.P is 91.