Question

15th term of AP 7 ,13, 19..

Answer 1

Answer:

$\rm 91$

Step-by-step explanation:

By using formula,

$\boxed{\rm a_n = a+(n-1)d}$

$\rm a_{15} = 7+(15-1)6$

$\rm = 7+(14)6$

$\rm = 7+ 84$

$\rm = 91$

Answer 2

Answer: 91

❍ Given :-

• AP → 7, 13, 19, •••

❍ To Find :-

• 15th term of AP given

❍ Solution :-

We have,

(13 - 7) = (19 - 13) = 6

Therefore, the given sequence is an A.P. with common difference 6.

➸ a = First term = 7

By using formula,

$\boxed{\sf{a_{n} = a + (n - 1)d}}$

∴ 15th term = $\sf a_{15}$ = a + (15 - 1)d = a + 14d

⇒ $\sf a_{15}$ = 7 + 14 × 6 = 91

Hence, 15th term of given A.P. is 91.

$\qquad \qquad \sf \green{Points} \: \red{To} \: \orange{Remember}:-$

✏ General term = nth term = a + (n - 1)d

✏ a = First Term

✏ d = Common Difference

✏ l = Last Term

✏ $\sf a_n$ = nth term