Math, asked by shivamnikam, 1 year ago

15x+17y=21;17x+15y=11 simulainious methode

Answers

Answered by AdorableAstronaut
20

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Given two equations are :

  • 15x + 17y = 21

  • 17x + 15y = 11

Solving the first equation,

15x + 17y = 21

15x = 21 - 17y

x =  \frac{21 - 17y}{15}

Now substituting the value of x in the second equation we get,

17( \frac{21 - 17y}{15}) + 15y \:  = 11

 \frac{357 - 289y}{15} + 15y = 11

Taking the LCM,

 \frac{357 - 289y + 225y}{15} = 11

Taking the denominator 15 to the other side,

357 - 289y + 225y = 15 \times 11 \\  \\ 357 - 64y = 165 \\  \\  - 64y =  - 192 \\  \\ y  =  \frac{ - 192}{ - 64} \\  \\ \boxed{ y = 3}

We got the value of y as 3.

Now substituting the value of y in equation 1,

15x   + (17 \times 3) = 21 \\  \\ 15x + 51 = 21 \\  \\ 15x = 21 - 51 \\  \\ x =  \frac{ - 30}{15} \\  \\  \boxed{ x =  - 2}

Hence, the value of x = -2 and the value of y = 3

Answered by Anonymous
3

Answer:

I hope it helps you....

peace ✌☺️

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