Question

15x^2+2x-8solve the trinomial by factorising ​

Answer 1

Answer:

below

Step-by-step explanation:

= 15x^2+2x-8

= 15x^2+12x+10x-8

= 3x(5x-4)+2(5x-4)

= (3x+2) (5x-4)

3x+2= 0    OR 5x-4 =0

x= -2/3 , 4/5

HOPS THIS HELPS

Answer 2

Answer:

$\large p(x)=(5x+4)(3x-2)$

Step-by-step explanation:

Given :

$\large p(x)=15x^2+2x-8$

We have to factorize the p ( x )

By splitting mid term method we get

$\large p(x)=15x^2+2x-8\\\\\\\large p(x)=15x^2+12x-10x-8\\\\\\\large p(x)=3x(5x+4)-2(5x+4)\\\\\\\large p(x)=(5x+4)(3x-2)$

Zeroes of p ( x )

$\large p(x)=(5x+4)(3x-2)\\\\\\\large (5x+4)=0 \ or \ (3x-2)=0\\\\\\\large (5x)=-4 \ or \ (3x)=2\\\\\\\large x=\dfrac{-4}{5} \ or \ x=\dfrac{2}{3}$

Thus we factorize and get zeroes too.