Question

15x^3y^2+5x^2y-20x^4y^3​

Answer 1

Step-by-step explanation:

write the question clearly what to do Ijjat to factorised?

Answer 2

Step-by-step explanation:

$15 {x}^{3} {y}^{2} + 5 {x}^{2} y - 20 {x}^{4} {y}^{3}$

Factor out. 5x²y from the expression

$5 {x}^{2} y(3xy + 1 - 4 {x}^{2} {y}^{2} )$

Use the commutative property to reorder the terms

$5 {x}^{2} y \times ( - 4 {x}^{2} {y}^{2} + 3xy + 1)$

Write 3xy as a difference

$5 {x}^{2} y \times ( - 4 {x}^{2} {y}^{2} + 4xy - xy + 1)$

Factor out -4xy from the expression

$5 {x}^{2} y \times ( - 4xy \times (xy - 1) - xy + 1)$

Factor out the negative sign from the expression

$5 {x}^{2} y \times ( - 4xy \times (xy - 1) - (xy - 1)$

Factor out. - ( xy - 1 ) from the expression

$5 {x}^{2} y \times ( - (xy - 1) \times (4xy + 1))$

Multiplying a positive and a negative equals as a negative : (+) × (-) = (-)

$- 5 {x}^{2} y \times (xy - 1) \times (4xy + 1)$

Here is your answer...