(15x÷4)<5(5x-2) - 3 (7x-3) find x?
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3
5x−2
−
5
7x−3
>
4
x
⇒
15
5(5x−2)−3(7x−3)
>
4
x
⇒
15
25x−10−21x+9
>
4
x
15
4x−1
>
4
x
⇒4(4x−1)>15x
[Multiplying both sides by 60 i.e. Lcm of 15 and 4]
16x−4>15x ⇒16x−15x>4[Transposing 15 x to LHS and -4 to RHS]
x > 4 ⇒x∈(4,∞)
Hence the solution set of the given inequation is (4,∞) This can be graphed on the real number line as shown in figure
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