Question

15x⁴+3x²-18 how to solve

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Answer 1

Step-by-step explanation:

15x^4+3x^2-18=0

3x^2(5x^2+1)-18

3x^2-18=0,5x^2+1=0

3x^2=18,5x^2=-1

3x=root18,5x=root-1

x=root 18/3,x=root -1/5

x=root6,x=root -1/5

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Answer 2

Step-by-step explanation

first let $x^{2}$=y

and put this in equation

15y^2+3y-18=0.................1

factorise

 p+q=3

p*q= -18*15= -270

equation 1 become

15y^2+18y-15y-18=0

3y(5y+6)-3(5y+6)=0

(5y+6)(3y-3)=0

(5y+6)=0

y=-6/5

(3y-3)=0

y=3/3

y=1

$x^{2}$= -6/5

x=√(-6/5)

x=±(6/5)i

x^2=1

x=±1

Final Answer

x=+(6/5)i,-(6/5)i,+1,-1